{"id":1311,"date":"2020-02-27T07:05:17","date_gmt":"2020-02-27T07:05:17","guid":{"rendered":"https:\/\/bcisnotes.com\/thirdsemester\/?p=1311"},"modified":"2020-02-27T07:14:47","modified_gmt":"2020-02-27T07:14:47","slug":"microprocessor-8085-programming-memory-location-part-2-microprocessor-bcis-notes","status":"publish","type":"post","link":"https:\/\/bcisnotes.com\/thirdsemester\/question-bank\/microprocessor-8085-programming-memory-location-part-2-microprocessor-bcis-notes\/","title":{"rendered":"Microprocessor 8085 programming (Memory Location) part 2 || Microprocessor || Bcis Notes"},"content":{"rendered":"

Microprocessor 8085 programming (Memory Location)<\/strong><\/h2>\n

1.\u00a0<\/strong>Six bytes are stored in memory location starting at 2050H. Add all the data bytes, save any\u00a0<\/strong>carry generated while adding the data bytes. Display\u00a0<\/strong>the entire sum at two output ports and store <\/strong>total carry in 2070H and sum in 2071H.<\/strong><\/p>\n

LXI H, 2050H
\nMVI C, 06H
\nMVI B, 00H
\nMVI D, 00H
\nL2: MOV A, M
\nADD B
\nMOV B, A
\nJNC L1
\nINR D
\nL1: INX H
\nDCR C
\nJNZ L2
\nHLT<\/p>\n

2. If the content of memory location 2050H is greater than or equal to 64H, display 0FH else <\/strong>display FFH.<\/strong><\/p>\n

LDA 2050H
\nCPI 64H
\nJC L1
\nMOV A, 0FH
\nOUT PORT 1
\nHLT
\nL1: MOV A, FFH
\nOUT PORT 1
\nHLT<\/p>\n

3. We have a list of data stored at a memory location starting at 2050H. The end of the data array <\/strong>is indicated by data byte 00H. Add the set of readings. Display the sum at Port 1 and total <\/strong>carry at Port 2.<\/strong><\/p>\n

LXI H, 2050H
\nMVI B, 00H
\nMVI C, 00H
\nL3: MOV A, M
\nCPI 00H
\nJZ L1
\nADD C
\nJNZ L2
\nINR B
\nL2: MOV C, A
\nINX H
\nJMP L3
\nL1: MOV A, C
\nOUT PORT 1
\nMOV A, B
\nOUT PORT 2
\nHLT<\/p>\n

4. There are two tables holding twenty data whose starting address is 3000H and 3020H <\/strong>respectively. WAP to add the content of the first table with the content of the second table having <\/strong>the same array index. Store sum and carry into the third and fourth table indexing from 3040H <\/strong>and 3060H respectively.<\/strong><\/p>\n

LXI B, 3000H
\nLXI H, 3020H
\nLXI D, 3040H
\nNEXT:\u00a0 \u00a0 \u00a0 LDAX B<\/p>\n

ADD M
\nSTAX D
\nPUSH H
\nPUSH D
\nJNC L1
\nMVI E, 01H
\nJMP CSTORE
\nL1:\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0MVI E, 00H
\nCSTORE: LXI H, 3060H
\nMOV A, L
\nADD C
\nMOV L, A
\nMOV M, E
\nPOP H
\nPOP D
\nINX B
\nINX D
\nINX H<\/p>\n

MOV A, C
\nCPI 14H
\nJNZ NEXT
\nHLT<\/p>\n

5. For ten bytes data starting from 1120H, write a program to sort the reading in ascending and <\/strong>in descending order. (Note: For descending, do self)<\/strong><\/p>\n

START: LXI H, 1120H
\nMVI D, 00H
\nMVI C, 0AH
\nL2:\u00a0 \u00a0 \u00a0 \u00a0 \u00a0MOV A, M
\nINX H
\nCMP M
\nJC L1
\nMOV B, M
\nMOV M, A
\nDCX H
\nMOV M, B
\nINX H
\nMVI D, 01H
\nL1:\u00a0 \u00a0 \u00a0 \u00a0 \u00a0DCR C
\nJNZ L2
\nMOV A, D
\nRRC
\nJC START
\nHLT<\/p>\n

6. A set of ten readings is stored in memory location starting at 1160H. The readings are <\/strong>expected to be positive (<127). WAP to<\/strong>
\n– Check each reading to determine whether it is positive or negative.<\/strong>
\n– Reject all negative readings.<\/strong>
\n– Add all positive readings & display sum in Port 1 and carry in Port 2.<\/strong><\/p>\n

MVI B, 00H
\nMVI C, 00H
\nMVI D, 0AH
\nLXI H, 1160H
\nL2:\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 MOV A, M
\nRAL
\nJC NEGLECT
\nRAR
\nADD B
\nJC L1
\nMOV B, A
\nL1:\u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 \u00a0 INR D
\nNEGLECT: INX H
\nDCR D
\nJNZ L2
\nMOV A, B
\nOUT PORT 1
\nMOV A, D
\nOUT PORT 2
\nHLT<\/p>\n

7. A set of six data bytes is stored starting from memory location 2050H. The set includes some <\/strong>blank spaces (bytes with zero values). WAP to eliminate the blanks from the block.<\/strong><\/p>\n

MVI C, 06H
\nLXI H, 2050H
\nLXI B, 2050H
\nL2: MOV A, M
\nCPI 00H
\nJZ L1
\nSTAX B
\nINX B
\nL1: INX H
\nDCR C
\nJNZ L2
\nHLT<\/p>\n

8. A set of eight data bytes (4 Pairs) are stored in memory locations starting from 1040H. WAP <\/strong>to add two bytes at a time and store the sum in the same memory location, sum replacing the first <\/strong>byte and the carry replacing the second byte. If any pair does not generate a carry, the<\/strong>\u00a0memory location of the second byte should be cleared i.e. store 00H over there.<\/strong><\/p>\n

MVI C, 04H
\nLXI H, 1040H
\nL2: MOV A, M
\nINX H
\nADD M
\nDCX H
\nMOV M, A
\nINX H
\nMVI M, 00H
\nJNC L1
\nMVI M, 01H
\nL1: INX H
\nDCR C
\nJNZ L2
\nHLT<\/p>\n

9. WAP to read BCD number stored at memory location 2020H and converts it into binary <\/strong>equivalent and finally stores that binary pattern into memory location 2030H. <\/strong>[Note: BCD number is the combination from 0 to 9]<\/strong><\/p>\n

MVI C, 0AH
\nLXI H, 2020H
\nMOV A, M
\nANI F0H
\nRRC
\nRRC
\nRRC
\nRRC
\nMOV B, A
\nMOV A, 00H
\nL1: ADD B
\nDCR C
\nJNZ L1
\nMOV D, A
\nMOV A, M
\nANI 0FH
\nADD D
\nSTA 2030H
\nHLT<\/p>\n

10. A binary number (Suppose FF: 1111 11112) is stored in memory location 2020H. Convert the <\/strong>number into BCD and store each BCD as two unpacked BCD digits in a memory location from <\/strong>2030H.<\/strong><\/p>\n

LXI SP, 2000H
\nLXI H, 2020HMOV A, M
\nCALL PWRTEN
\nHLT
\nPWETEN: LXI H, 2030H
\nMVI B, 64H
\nCALL BINBCD
\nMOV M, D
\nINX H
\nMVI B, 0AH
\nCALL BINBCD
\nMOV M, D
\nINX H
\nMOV M, A
\nRET
\nBINBCD:\u00a0 \u00a0MVI D, 00H
\nNEXT:\u00a0 \u00a0 \u00a0 \u00a0INR D
\nSUB B
\nJNC NEXT
\nDCR D
\nADD B
\nRET
\nHLT<\/p>\n

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