{"id":1512,"date":"2021-04-25T17:51:15","date_gmt":"2021-04-25T12:06:15","guid":{"rendered":"https:\/\/bcisnotes.com\/secondsemester\/?p=1512"},"modified":"2021-04-25T17:57:55","modified_gmt":"2021-04-25T12:12:55","slug":"pokhara-university-semester-spring-2015-digital-system","status":"publish","type":"post","link":"https:\/\/bcisnotes.com\/secondsemester\/question-bank\/pokhara-university-semester-spring-2015-digital-system\/","title":{"rendered":"Pokhara University Semester Spring 2015 || Digital System || BCIS"},"content":{"rendered":"

Spring 2015 Digital Systems<\/h3>\n

This is the question set along with the answers of Spring 2015 Digital Systems which was taken by the Pokhara University (PU).<\/p>\n

POKHARA UNIVERSITY(PU)<\/span><\/b>\u00a0<\/span><\/p>\n\n\n\n\n\n\n\n\n
Level:\u00a0 Bachelor<\/span><\/b>\u00a0<\/span><\/td>\nSemester \u2013 <\/span><\/b>Spring<\/span><\/b>\u00a0<\/span><\/td>\nYear: 201<\/span><\/b>5<\/span><\/b>\u00a0<\/span><\/td>\n<\/tr>\n
Program: BCIS<\/span><\/b>\u00a0<\/span><\/td>\nFull Marks: 100<\/span><\/b>\u00a0<\/span><\/td>\n<\/tr>\n
Course: Digital Systems<\/span><\/b>\u00a0<\/span><\/td>\nPass Marks: 45<\/span><\/b>\u00a0<\/span><\/td>\n<\/tr>\n
\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Time:3hrs<\/span><\/b>\u00a0<\/span><\/td>\n<\/tr>\n
Candidates are required to give their answers in their own words as far as practicable.<\/span><\/i>\u00a0<\/span><\/td>\n<\/tr>\n
The figures in the margin indicate full marks.<\/span><\/i>\u00a0<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

\u00a0<\/span>\u00a0<\/span><\/p>\n

Section \u201cA\u201d<\/span><\/b>\u00a0<\/span><\/p>\n

Very Short Answer Questions<\/span><\/b>\u00a0<\/span><\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n
SN<\/span>\u00a0<\/span><\/td>\nAttempt all the questions.<\/span><\/b>\u00a0<\/span><\/td>\n10\u00d72<\/span><\/b>\u00a0<\/span><\/td>\n<\/tr>\n
1<\/span>\u00a0<\/span><\/td>\nWhat do you mean by digital syste<\/span>m?<\/span>\u00a0<\/span><\/td>\n2<\/span>\u00a0<\/span><\/td>\n<\/tr>\n
2<\/span>\u00a0<\/span><\/td>\nWhat is bit?<\/span>\u00a0<\/span><\/td>\n2<\/span>\u00a0<\/span><\/td>\n<\/tr>\n
3<\/span>\u00a0<\/span><\/td>\nWhat is XOR gate?<\/span>\u00a0<\/span><\/td>\n2<\/span>\u00a0<\/span><\/td>\n<\/tr>\n
4<\/span>\u00a0<\/span><\/td>\nWhat is encoder?<\/span>\u00a0<\/span><\/td>\n2<\/span>\u00a0<\/span><\/td>\n<\/tr>\n
5<\/span>\u00a0<\/span><\/td>\nWhat is flipflop?<\/span>\u00a0<\/span><\/td>\n2<\/span>\u00a0<\/span><\/td>\n<\/tr>\n
6<\/span>\u00a0<\/span><\/td>\nWhat do you mean by triggering of flipflop?<\/span>\u00a0<\/span><\/td>\n2<\/span>\u00a0<\/span><\/td>\n<\/tr>\n
7<\/span>\u00a0<\/span><\/td>\nWhat is memory?<\/span>\u00a0<\/span><\/td>\n2<\/span>\u00a0<\/span><\/td>\n<\/tr>\n
8<\/span>\u00a0<\/span><\/td>\nExplain CMOS.<\/span>\u00a0<\/span><\/td>\n2<\/span>\u00a0<\/span><\/td>\n<\/tr>\n
9<\/span>\u00a0<\/span><\/td>\nWhat is ALU?<\/span>\u00a0<\/span><\/td>\n2<\/span>\u00a0<\/span><\/td>\n<\/tr>\n
10<\/span>\u00a0<\/span><\/td>\nWhat is k-map?<\/span>\u00a0<\/span><\/td>\n2<\/span>\u00a0<\/span><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

\u00a0<\/span><\/p>\n

Section \u201cB\u201d<\/span>\u00a0<\/span><\/p>\n

Descriptive Answer Questions<\/span><\/b>\u00a0<\/span><\/p>\n

Attempt any six questions.<\/span> 6X10<\/span>\u00a0<\/span><\/p>\n

1<\/span>1<\/span>.Simplify the following expression<\/span>.<\/span> \u00a0<\/span><\/p>\n

\u03a3<\/span>m<\/span> (0, 2, 5, 9, 15) +<\/span> \u03a3<\/span>d<\/span> (1, 4, 7, <\/span>12)<\/span>\u00a0<\/span><\/p>\n

Using K-map and draw the logic diagram using<\/span>\u00a0<\/span><\/p>\n

    \n
  1. Basic gates only<\/span>\u00a0<\/span><\/li>\n<\/ol>\n
      \n
    1. NAND gates only<\/span>\u00a0<\/span><\/li>\n<\/ol>\n

      1<\/span>2<\/span>.<\/span>Difference between multiplexer and demultiplexer. Design Full Adder using two half adder and OR gate.<\/span>\u00a0<\/span><\/p>\n

        \n
      1. 1<\/span>3<\/span>. <\/span>Write short notes on<\/span>.<\/span><\/li>\n
      2. Status register<\/span><\/li>\n<\/ol>\n

        \u00a0\u00a0 Ii. 4-bits ALU<\/span>\u00a0<\/span><\/p>\n

          \n
        1. 1<\/span>4<\/span>. <\/span>What do you mean by a counter? Design a 3-bit synchronous counter.<\/span><\/li>\n<\/ol>\n

          1<\/span>5<\/span>.<\/span>Explain in detail about the operation of JK flipflop along with truth tabl<\/span>e<\/span>, characteristics equation<\/span> and circuit diagram.<\/span>\u00a0<\/span><\/p>\n

          16.Convert the following number from the given base to the other bases indicated.<\/span>\u00a0<\/span><\/p>\n

            \n
          1. (4F.D2)<\/span>=<\/span> ( )<\/span>8<\/span>\u00a0<\/span>\u00a0<\/span><\/li>\n<\/ol>\n
              \n
            1. (<\/span>1101-101<\/span>16\u00a0 <\/span>)<\/span>2<\/span>\u00a0 <\/span>using<\/span> 1\u2019s complement method.<\/span>\u00a0<\/span><\/li>\n<\/ol>\n
                \n
              1. (<\/span>762<\/span>)<\/span>8<\/span> x<\/span>(<\/span>345<\/span>)<\/span>8<\/span>\u00a0<\/span><\/li>\n<\/ol>\n
                  \n
                1. \u00a0 Find base If <\/span>(<\/span>2<\/span>11)<\/span>x<\/span> = (<\/span>152<\/span>)<\/span>\u00a0<\/span><\/li>\n<\/ol>\n
                    \n
                  1. A) State and prove De Morgan\u2019s theorem<\/span><\/li>\n
                  2. \u00a0 \u00a0 B) Prove the universality of NAND and NOR gates?<\/span>\u00a0<\/span><\/li>\n<\/ol>\n

                    Section\u201d C<\/span>\u201d<\/span>\u00a0<\/span><\/p>\n

                    Case Study<\/span><\/b>\u00a0<\/span><\/p>\n

                      \n
                    1. A BCD to seven segment decoder is a combinational circuit that accepts a decimal in <\/span>BCD and<\/span> generates the appropriate outputs<\/span> decimal digit. The seven outputs <\/span>of decoder (a, b, c, d, e, f, g) select the corresponding segments in the display. Design the <\/span>BCD to seven segment decoder circuit<\/span> (<\/span>20)<\/span><\/li>\n<\/ol>\n

                      \u00a0<\/span><\/b> \u00a0<\/span><\/p>\n

                      \u00a0You May Also Like:\u00a0\u00a0Pokhara University || Fall 2015 Digital Systems|| BCIS<\/a><\/span><\/p>\n

                      <\/div>